I have a math question. or two. can you please show me how to do them. i am so confused.?

Question

the first on is 16x to the fourth power -1. so its 16x4 -1. its solving quadratic equatoins. the next one is 6a the the second power -28-48. so 6a2-28a-48. the next one is -75x to the 3rd power+ 60x to the 2nd power-12x. so -75x3+60x2-12x.

the next and last one is y(4y-6)=0.

Thank you so much!

Answer 1

It's not an equation without an equals sign.  You want to factor them?

16x^4 -1

(4x^2 + 1)(4x^2 - 1)

difference of two squares

http://www.regentsprep.org/Regents/Math/...

6a^2 - 28a - 48

2(3a^2 - 14a - 24)

2(3a + 4)(a - 6)

http://www.regentsprep.org/Regents/Math/...

http://www.regentsprep.org/Regents/Math/...

-75x^3 + 60x^2 - 12x

-3x(25x^2 - 20x + 4)

-3x(5x -2 )(5x -2  )

-3x(5x - 2)^2

y(4y-6)=0

y = 0 and/ or 4y - 6 = 0

y = 0 and/ or y = 6/4

Answer 2

nope.....u should do your math homework or test yourself....

Answer 3

Question 1

16x^4 -1

(4x^2 - 1)(4x^2 +1)

the first one can be broken down further to

(2x +1)(2x - 1)(4x^2 +1)

Question 2

6a^2 - 28a - 48

(3a +4)(2a - 12)

Question 3

-75x^3 + 60x^2 - 12x

factor out a -3x

-3x ( 25x^2 - 20x  + 4)

-3x (5x - 2)^2

Question 4

y(4y - 6) = 0

divide both sides by y

4y - 6 = 0

4y = 6

y = 3/2

Answer 4

Try this http://www.quickmath.com/

Answer 5

You first have to find out the factors of 16 and 1 separately. 1, 4, 16 are factors of 16 and 1 is the only factor of 1. Then, you need to find a combination of the factors to get the coefficient of the 1st degree term x.  In this case, coefficient of term x = 0.  So, it should be:

Q1) 16x^4-1

= (4x^2+1)(4x^2-1)

Q2) 6a^2-28a-48

= 2(3a^2-14a-24)

= 2(3a+4)(a-6)

It's hard to explain, hope you understand.  Try to do the other questions yourself and see if you understand.

Answer 6

http://answers.yahoo.com/question/index?...

Answer 7

1. 16x^4-1=0,

16x^4=1,

x^4=1/16,

x= plus or minus 1/2. Make sure plus 1/2 and minus 1/2 are both the answers, and both need to be noted, as per your teacher, which I am guessing (s)he probably wants.

2. 6a^2-28a-48=0

3a^2-14a-24=0,

3a^2-18a+4a-24=0,

3a(a-6)+4(a-6)=0,

(3a+4)(a-6)=0

a=-4/3 or a=6.

3.y(4y-6)=0,

thus, y=0 or 4y-6=0

thus, y=0 or 4y=6

thus, y=0 or y=3/2. Again, two answers.

Hope that helps.

Answer 8

I'll do the rest.  If you can't do the rest, you're in real trouble and it's not even September.

16x^4 - 1 = 0  (add 1 to both sides)

16x^4 = 1  (divided both sides by 16)

x^4 = 1/16  (square root both sides)

x^2 = 1/4 or x^2 = -1/4  (square root both sides again)

x = 1/2 or x = -1/2 or x = i/2 or x = -i/2