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I have a question about a physics about maximum falling speed

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i need to find some sort of formula for how to find the speed of a falling object - i have a certain height, and this is before it can reach terminal velocity of 9.8 m/s - the height i have is 41.67 m, and a mass of 7500kg (incase you are wondering, this is a roller coaster, but this particular question is asking if there was no friction what would be the maximum speed?)

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  1. If the question assumes no friction, then there is no terminal velocity. Just treat the problem as conservation of energy. The potential energy at the top equals the kinetic energy at the bottom. m g h  =  1/2 m v^2

    The mass drops out and we get v  =  sqr rt of (2 g h). The result is about 29 m/s.


  2. instantaneous velocity

    v = gt = √(2dg)

    g = 9.8 m/s²

    So an object free falling (not a roller coaster) from 42 m will be moving at:

    v = √(2*42*9.8) = 29 m/s

    "terminal velocity of 9.8 m/s" wrong, it's about 90 m/s

    .

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