Question:

I have a question on quadratic equation?

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I have like no idea how to draw the equation. It goes up and down several times, but I just don't get it.

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  1. Heh.  Here's a little trick that will work for these graphs.  If you are TOTALLY screwed up and can't remember any of the rules, all you have to do is plot some test points and you will be able to figure the rest out.

    So if you had x^2-6x+9  then you make a table and pick some random x points and solve.  So in this case you would have:

    x       y

    -2      25

    -1      16

    0       9

    1       4

    2        1

    3        0

    4        1

    5        4

    6        9

    etc

    Then when you plot a few points you will see how the graph is.

    Good luck.


  2. i can help you..but a dont understand your question

  3. you need to give more detail

    we dont know the problem you have

    if its an algebra 1 quad eq it should just be a parabula

    looks like a U

    or upside down U..

    give more specifics...

  4. substitute 0 for x and solve for y.  That will get you a y-intercept.  set y equal to zero and solve for x.  you can do this by factoring or using the quadratic formula.  the answer will give you the x intercepts.  then if you need any more points plug in really easy x values such as 1, 2 , etc etc.  It will end up as a U shape.  either pointing up or down.  This is if it is x squared mind you.

  5. http://en.wikipedia.org/wiki/Quadratic_e...

    http://mathworld.wolfram.com/QuadraticEq...

    http://www.wtamu.edu/academic/anns/mps/m...

    http://www.helpalgebra.com/articles/quad...

    http://www.answers.com/topic/quadratic-e...

  6. f(x)=a+x+x^2

  7. go to    math.com

    everytime i need help on geometry or algebra i always go there

  8. are you graphing. I have the Algebra book right in front of me. just write back and i will help you out ok? also please answer my ?

    You Should Tell Me More About it By Answering My Question. Trust ME It Will Help.

    http://answers.yahoo.com/question/index;...

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