I have a triangle lot that measures 348 X 735 X 835. What is the total acreage and how is it calulated?

Question

I have a triangle lot that measures 348 X 735 X 835. What is the total acreage and how is it calulated?

Answer 1

- 1/2 the length of the base then times that by the height...use if you know the base and the height

- base times the height, the answer is then divided by two...use if you know the base and the height

- "1/2 ab sin C" using the diagram below (forget about the other side..use if you know an angle and the two sides on the outside of it.

a(side on top

v

< - C (the angle)

^

b(side on bottom

convert to acres.

Answer 2

1.  Find the area thus:

A = sqrt{s x (s-a) x (s-b) x (s-c)}  where a,b,c are the length of each side and s = (a + b + c)/2

2. Assuming the given dimensions are in feet, find the number of acres by dividing the area A by 43,560 (the number of sq ft in an acre).

3. Therefore, since s =959;

A = sqrt {959 x (959-348) x (959-735) x (959-835)}

A = sqrt {959 x 611 x 224 x 124}

A = 127,574.76 sq ft

Acreage = 2.929