I have no idea how to solve this, can someone please help me j^(-4/3)-13j^(-2/3)+36=0?

Question

alright thanks for the help, i get it now

Answer 1

Let  j^(-2/3) be X then

X^2 - 13X + 36 = 0

(X - 9) (X - 4) = 0

X = 9 or X = $

So

j^-2/3 = 9  Power to (-3/2) both side

j = 9^(-3/2) = j = 1/27

j^-2/3 =4 --> j = 1/8

Answer j = 1/27 or j = 1/8

Answer 2

Let x = j^-2/3.  Then

j^(-4/3) - 13j^(-2/3) + 26 = x^2 - 13x + 36 = 0

Solve the quadratic.  Resubstitute and solve the two equations you end up with.