I have two math problems i can't solve. help?

Question

the first one is 3m<-6 or 2m+7>13 (the problem actually says or.

the second one is 4x+3y=-1

-3x-2y=3

Answer 1

2m + 7 &gt; 13                  

2m &gt; 6

m&gt; 3

3m &lt;-6

m&lt;-2

Therefore -2&lt;m&lt;3

For this next problem you will want to get one of the variables to cancel out since you can&#039;t work with 2 unknowns.

(4x+3y = -1)2

(-3x -2y = 3)3

8x +6y = -2

-9x -6y = 9

-x = 7

x = -7

Plug this back into either of the equations given in the beginning.

4(-7) +3y = -1

-28 +3y = -1

3y = 27

y=9

Answer 2

The first person was correct on the second one, but not on the first one. I also want to clarify the second one.

On the first one he said

2m + 7 &gt; 13

2m &gt; 6

m&gt; 3

3m &lt;-6

m&lt;-2

Therefore -2&lt;m&lt;3

However, if m&gt;3 and m&lt;-2, then the answer is

either m&gt;3 or m&lt;-2. The only thing we know for sure is that m is not between -2 or 3.

On the second one, where he said

8x +6y = -2

-9x -6y = 9

-x = 7

x = -7

To elaborate how he got to -7

8x + 6y = -2

6y = -2 - 8x

-9x - 6y = 9

-6y = 9 + 9x

multiply both sides by -1

6y = -9 - 9x

so 6y is both -9 - 9x and -2 - 8x

-9 -9x = -2 - 8x

-9 -9x +9x= -2 -8x +9x

-9 +2= -2 -8x +9x +2

-7 = -1x

-1(-7) = -1(-1x)

7 = x