I need equation help! 4x^4-18x^2=0 Explain in detail how its solved!! ?

Question

I am not a strong math student but I want to learn!!

Answer 1

Factor out x^2:

x^2(4x^2 -18) =0

x^2 = 0

x =0

4x^2 = 18

x^2 = 18/4 = 4.5

x = + or - sqrt4.5

Answer 2

4x4-18x2=0

2x2(x2-9)=0

2x2(x-9)(x+9)=0

so 2x2=0 or x-9=0 or x+9=0

so x=0, 9, -9

Answer 3

4x^4-18x^2=0

2x^2(2x^2-9) =0

So IF

2x^2 = 0

.x = 0

OR

2x^2 - 9 = 0

2 x^2 = 9

x^2 = 9 /2

x = √ 9/2

x = ± 3 / √2

x = (3/2)/√2 or  -(3/2)√2