I need help! It's a math question, thanks!?

Question

Suppose you have a bunch of wooden beds, each weighing 200 pounds each, arranged in a pyramid. The base layer is 5 beds by 5 beds, the layer above is 4 beds by 4 beds, and so on until the top layer of one bed. They are arranged in such a way that each bed is resting on four beds below it, one leg on each bed.

If the weight on each bed is always equally distributed to all four legs, and each bed leg can only support 200 pounds, how many pounds can you place on top of the topmost bed? Please round to the nearest pound, and plese submit only a single number as your answer

thanks!

Answer 1

9th copy of the same question posted in the last hour of this question

See http://answers.yahoo.com/question/?qid=2...

for detailed answer.

Answer 2

(.25 x 200) = the weight added with each additional bed

Given that the inmost beds will have 4 legs on them in the first, second and third layers and only 2 for the last two layers (because in a 2 x 2 or 1  x 1 there is no inner bed and each bed in the second layer will only support 1 leg:

x = amount of weight possible on the top bed

(.25 x 200) = 50 so

[(50 x 4) 3] + 50x = 200 and this will go into negative numbers.

Either there's something missing or this is a trick question.  If we include the weights of the beds themselves in our equation, the beds in the bottom level middle are maxed out at the addition of the 2nd layer.  

Answer 3

Zero. The bed at the very center of the pyramid on the ground level is at its maximum capacity.