Question:

I need help!!! about vector rectangular, cylindrical ,and sphrical coordinates problem!! Help me please?

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(Electromagnetism)

Can someone help me with this problem?? cuz i need it up till tommorow

At point P(-3,-4,5), express that vector that extends from P to Q(2,0,-1)in:

(a) rectangular coordinates;

(b) cylindrical coordinates ;

(c) spherical coordinates.

(d) Show that each of these vectors has the same magnitude

Please help me .... thnk you and God Bless!!

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1 ANSWERS


  1. Let, Unit Vectors :

    Rectangular  coordinates : (a_x), (a_y), (a_z).

    Cylindrical coordinates : (a_ro), (a_phi), (az)

    Spherical Coordinates : (a_r), (a_theta), (a_phi)

    (a)

    The vector from P to Q in rectangular coordinates is :

    PQ = {2-(-3)}(a_x) + {0-(-4)}(a_y) + (-1-5)(a_z)

    = 5(a_x) + 4(a_y) - 6(a_z)

    Magnitude = sqrt(5^2 + 4^2 + 6^2)

    (b)

    PQ_ro = {5(a_x) + 4(a_y) - 6(a_z)} . (a_ro)

    = 5cos(phi) - 8sin(phi)

    Simiplarly, PQ_phi = PQ . (a_phi) = -10sin(phi) - 8cos(phi)

    PQ_z = -6

    ro = sqrt(5^2 + 4^2)

    phi = tan(inverse)(4/5)

    put the value of phi to find PQ_ro, PQ_phi, PQ_z

    PQ in cylindrical coordinate is PQ_ro + PQ_phi + PQ_z

    (c)

    PQ_r = PQ . (a_r)

    PQ_theta = PQ . (a_theta)

    PQ_phi = PQ . (a_phi)

    Hint :

    a_x . a_r = sin(theta)cos(phi)

    a_x . a_theta = cos(theta)cos(phi)

    a_x . a_phi = -sin(phi)

    a_y . a_r = sin(theta)sin(phi)

    a_y . a_theta = cos(theta)sin(phi)

    a_y . a_phi = cos(theta)

    a_z . a_r = cos(theta)

    a_z . a_theta = -sin(theta)

    a_z . a_phi = 0

    find r = sqrt(5^2 + 4^2 + 6^2)

    theta = cos(inverse) (-6/r)

    phi = tan(inverse) (4/5)

    Finally, PQ in spherical coordinates :

    PQ = (PQ_r)(a_r) + (PQ_theta)(a_theta) + (PQ_phi)(a_phi)

    Find the magnitudes as you did earlier.

    All the best.

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