I need help figuring this question out.?

Question

Nondisjunction occurred to produce a child with x*x from normal male and female parents. In order to determine in which parent the nondisjunction event occurred, DNA fingerprinting was performed. The female has the following genotype: XA Xa, where the A/a refers to which allele she has on her X chromosome. The Father’s genotype is XA Y. The child’s genotype was determined to be XA XA Xa . There are 2 different ways that this child could have received this genotype via nondisjunction of one of the parents.

List BOTH correct answers to this question: In which parent did nondisjunction occur and during which round of meiosis did it occur?

Answer 1

Because the kids DNA is XAXAXa the disjunction must have happened in mom's gamete because she is the parent who has an Xa allele.

Answer 2

The nondisjunction event could have occurred in either:

1) the mother, during meiosis I of oogenesis (i.e. the development of a primary oocyte to a secondary oocyte).  This would produce a gamete (ovum) with XA/Xa.  If this gamete is fertilized by a sperm with an XA chromosome from the father, the resulting child would be XA/XA/Xa.

2) the father, during meiosis II of spermatogenesis (i.e. the development of a secondary spermatocyte to a spermatid).  This would produce a gamete (spermatozoa) with XA/XA.  If this gamete is used to fertilize an ovum with an Xa chromosome from the mother, the resulting child would be XA/XA/Xa.