Question:

I need help on mi algebra homework 3+4x=9x+13?

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u need to show me how u got tha answer to receive tha 10 points

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  1. 3+4x=9x+13

      -4x  -4x

    3=5x+13

    -13    -13

    -10=5x

    divide but 5 on each side

    -2=x


  2. ok. first you move 4x to the other side and simplify so you end up with 3= 5x + 13. then you move the 13 to the other side and simplify so you get  -10= 5x. then, to find x, you divide both sides by 5 so you end up with x = -2. i hope i helped!

  3. 3=5X+13

    -10=5X

    -2=X

    **you combine like terms...

  4. 3+4x=9x+13

    Subtract 4x from both sides to get:

    3=5x+13

    Then subtract 13 from both sides to get:

    -10=5x

    Divide both sides by 5 to get:

    -2=x

    I hope this helped!

  5. 3+4x=9x+13

       -4x   -4x

         3=5x+13

       -13      -13

       -10=5x

    then divide both sides by 5 and you should get -2 so the answer is

    x= -2

  6. 3+4x=9x+13

    -3            -3

    4x=9x+10

    -4x -4x

    0=5x+10

    -10     -10

    -10=5x

    /5     /5

    -2=x

  7. solving this problem is a simple matter of inverse operations.

    To solve this problem, we first subtract 4x from both sides of the equation.

    3+4x-4x=9x+13-4x (Now we combine like terms. Basically you add the x's. the +4x and the -4x cancel each other out, so its like they're not there)

    3=5x+13 (subtract 10 from both sides of the equation)

    3-13=5x+13-13(The +13 and the -13 cancel each other out)

    -10=5x( divide by 5)

    -10/5=5x/5 (The 5 in the numerator and the denominator cancel each other out to give you a factor of 1

    x= -2   <====ANSWER

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