I need help solving this Algebra problem?

Question

How can i solve this 2(3x-1)^2? Do i square the whole parenthesis by 2? someone please help me with this, thanks

Answer 1

Usually this means

2((3x-1)^2)

2(6x^2 - 6x + 1)

12x^2 - 12x + 2

Answer 2

2(3x-1)^2

square the parentheses

2(9x²-6x+1)

multiply by two

18x²-12x+2

Answer 3

Delta has it correct.

First you square (3x-1) and then multiply that answer by 2. Thus leaving you with an answer of 18x^2 -12x+2.

(3x-1)(3x-1) = 9x^2-6x+1

2(9x^2-6x+1) = 18^2-12x+2.

Hope this helps!

Answer 4

2times3x-1 yes you square the whole parenthesis . i need help with mine too please help http://answers.yahoo.com/question/index;...

Answer 5

Yes, you do square the entire expression inside the parentheses:

2(3x - 1)^2 = 2*(9x^2 - 6x + 1) = 18x^2 - 12x + 2.  

Answer 6

Yes the whole parenthesis gets squared.