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I need help to simplify a math question... 3y-4[x-2(5-4x)-y]?

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please explain I haven't taken math in 5 years and I'm in an intermediate algebra class

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     3y-4[x-2(5-4x)-y]                                             formula

   =3y-4[xCy0+8x-y]                                          1)+* + = +

   =3y-4[9*10-y]                                                 2)- * -  = +

   =3y-36x+40+4y                                              3)-  * + = -

   =3y-36x+44y

   =3y-80xy

   =77xy





Report (0) (0) |   earlier
remember pemdas, so do the parens first.

3y-4[x-2(5-4x)-y]

3y-4[x-(10-8x)-y]

3y-4[x-10+8x-y]

3y-4[9x-10-y]

3y -(36x - 40 -4y)

3y - 36x + 40 + 4y

7y - 36x + 40
Report (0) (0) | earlier
follow BODMAS - ie first brackets then divide multiply add and subtract

so open the inner most bracket first and then move outwards

3y-4[x-10+8x -y]

3y -36x + 40 +4y

7y -36 x + 40

AM
Report (0) (0) | earlier
3y - 4[x - 2 ( 5 - 4x ) - y]              {first need to expand brackets}

3y - 4[x - 10 + 8x - y]          {times everything in the brackets by (-) 4

3y - 4x + 40 - 32x + 4y                 {then simplify}

7y - 36x + 40

hopefully that helps you :)
Report (0) (0) |   earlier
so first do the operation in the brackets [x-2(5-4x)-y] remember that multiplication is always first... so...(-2)(5-4x) after multiplying it out u get...-10+8x so you have then subtract y bc its in the brackets... so u have...3y-4[x-10+8x-y]after simplifying u get...3y-4[-10+9x-y].. after multiplying u get...-30y+40+27x^2-36x-3y^2+4y...-26y+4...
Report (0) (0) | earlier
3y-4[x-2(5-4x)-y]

=3y-4[x-10+8x-y]

=3y-4[9x-y-10]

=3y-36x+4y+40

=7y-36x+40 ..ans
Report (0) (0) | earlier