I need help with Calculus...?

Question

x^3 - x^2 + 2x - 2

I know this deals with factoring, but I'm not sure how to do it...

Help please?

Answer 1

By subtituting x = 0; +/-1; +/- 2; etc...

When sub x = 1; the expression is 0 (zero)

therefore x = 1 is a solution of the x^3 - x^2 + 2x - 2 = 0

or (x-1) is a factor of expression x^3 - x^2 + 2x - 2

Using the diving polynomial by a polynomial (in this case is binomial)

we have:

x^3 - x^2 + 2x - 2 = (x - 1)(x^2 + 2)   done..

Answer 2

what you have written is incomplete.  it is like writing half a sentence.  does this equal something?  do you need to know intercepts, inflections, etc.?  

Answer 3

factoring? straight factoring isn't calculus.

are you doing limits?

the derivative:

f ' (x)=3x^2-2x+2

the integral:

F(x)= (1/4)x^4-(1/3)x^3+x^2-2x+c