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Question

A minor league baseball team plays 109 games in a season. If the team won 13 more than three times as many games as they lost, how many wins and losses did the team have?

1. How many games did the team lose

2. How many games did the team win

Answer 1

this should be in the math section, not the baseball section, but I'll help you anyway

wins + losses = 109 games total

Wins = losses +13 (substute this into the first equation)

(Losses +13) + losses = 109

2 x losses + 13 = 109

2 x losses = 96

losses = 96/2 = 48

wins = 109-48 = 61

The team had 61 wins, 48 losses.

Answer 2

Even though your technically in the wrong section, i'll be happy to help

x= no. of how much they lost

3x+13= no. of how much they won

x+3x+13= 109 -add the x and 3x together

4x+13=109 -subtract 13 from both sides

4x=96 - divide both sides by 4

x= 24 -thats your answer for no. of how much they lost

3x+13= 3(24)+13= 72+13= 85 - how much the won

they lost 24 games and won 85.

Answer 3

W + L = total games played

W + L = 109

let L be the number of losses

so # games won = 13 + 3L

and # games lost = L

so 13 + 3L + L = 109

4L = 96

L = 24

so the team lost 24 games

13 + 3*24 = 13 + 72 = 85 games won

to check yourself

85 + 24 = 109

Answer 4

they lost 24 games

they won 85 games