I need help with my Algebra II homework!?

Question

Okay, here are the problems.

x + y = 7

y + z = 8

x + 2z = 2

Also.

5x + y + 6z = 3

x - y + 10z = 9

5x + y - 2z = -9

Please, do not just give me the answers...explain the problem.

I need this ASAP! Thanks.

Answer 1

Okay if you're trying to find what x, y, and z equal then pick a variable to solve for and keep plugging it into your other equations until you get what all of your variables equal.  I hope that makes sense.

Answer 2

This is what teachers are for, they get paid to teach and help the students, you just have to ask.

Answer 3

Ok well lets just start with the first one...

x+y=7

what you are trying to do to solve this is get one variable on one side of the equals sign by itself so do to that in this particular problem you are going to subtract the other variable from each side, since the problem is addition. So...

y=7-x

and that is your answer. It can also be written 7-x=y

You should do the same exact thing on the next problem.

The third problem is just the same too. x=2-2z... i think. u might want to check with someone and make sure on this one...

Also try and get help on the last set of problems I think i know how to do them but and not 100% sure and i don't want you to get them wrong becuase of me. But i am positive the first 2 i helped you with are correct. Good Luck!

Answer 4

I don't take algebra II, but I'm guessing that

(first one)

   If X +2z=2, Then all I have to do is say, well, What times '2' + what is still equal to 2, and fit the others....

Well, since 2 is added and multiplied, and yet is STILL the sum of 2, then think, what plus/multipled by what (in this case 2) gives me the same number as before. Simple, really. Add a 0 to anything, you get the other number (2) and multiply 1 by anything you get that other numer, which is, again, '2.'  See if it's right by plugging the 0 and 1 in.

        0

Because you add anything, you get the other #,

   0+2x1

Because anything times 1 is that other number  (and anytime you have a smaller number like that next to it, I'm sure you know, means to multiply)

    0+2x1=2.

so, X=0 and Z=1. But what about the others? And 'Y'?? You have to plug them in.

    X+Y=7

You already know...   0+Y=7... since you plg it in

But, still, what about Y, sure you've figured it out. Anything plus 0 equals itself, of cours, so Y could only equal to 7.

If Y=7 then what's Z?  

       Y+Z=8, plugging things in, it's  7+1=8

You add in what you think 'Z' is. -thus getting your answer, and checking your answer. If 'Z' doesn't plug into the one of the equations, yet plugs into the first one, that would mean the number you chose would be incorrect.

  Here, your answer is

X=0

Y=7

Z=1

As for the last one, I'm very sorry, but I don't really know.

All I can say, is try using process of elimination. Plug in numbers, and if they don't fit all of the equations, then it's not that number. I'm sorry.

Good luck, and hope I helped!

Answer 5

basically these are systems of equations.. the only way to solve these is to manipulate them and add/subtract the... for example you could multiple the 2nd equation by 2 and subtract so you only have x and y... or u could use substitution.. rewrite x + y =7 to x= 7-y and substitute to find y... and so on