I need help with physics... =/?

Question

We will now use energy considerations to find the speed of a falling object at impact. Artiom is on the roof replacing some shingles when his 0.55 kg hammer slips out of his hands. The hammer falls 3.67 m to the ground. Neglecting air resistance, the total mechanical energy of the system will remain the same. The kinetic energy and the gravitational potential energy possessed by the hammer 3.67 m above the ground is equal to the kinetic energy and the gravitational potential energy of the falling hammer as it falls. Upon impact, all of the energy is in a kinetic form. The following equation can be used to represent the relationship:

GPE + KE (top) = GPE + KE (at impact)

Because the hammer is dropped from rest, the KE at the top is equal to zero.

Because the hammer is at base level, the height of the hammer is equal to zero; therefore the PE upon impact is zero.

We may write our equation like this:

GPE (top) = KE (at impact)

This gives us the equation:

( mgh) (top) = 1/2 mv2 (at impact)

A. - Notice that the mass of the hammer "m" is shown on both sides of the equation. According to the math rules we have learned, what does this mean?

B. - Manipulate the equation (rearrange the variables) to solve for v. (Remember that manipulating an equation does not involve numbers and substitutions. You just rearrange the equation. v = ?)

C. - Use your equation from part B to find the speed with which the hammer struck the ground.

Answer 1

½ mv² = mgh -- the m's canel out

v = √2gh -- rearange and solve for v

v = √2 * 9. 8 * 3,67

v = 8.481 m/s

Answer 2

A.  mass stays the same before and after the hammer is dropped (although i'd argue that a negligible microscopic bit of the hammer broke off on impact), so dividing both sides of the equation by m (effectively eliminating m from the equation altogether) and manipulating it a bit yields an equation that you should recognize.... acceleration due to gravity!

B.  v = square root of (2gh)

C.  plug in the numbers... h =3.67 meters, g=9.8 meters per second per second (a constant at sea level)

so v = 8.48 m/s  the mass doesn't matter!!!