I need help with this problem!!!! it deals with restrictions.?

Question

4/9(x+3)=g. solve for x.State any restrictions on the variables.

Answer 1

x not to be -3.

Answer 2

x = 4g/9-3 , x!= 0

Answer 3

Your statement of the problem is ambiguous, probably because you failed to add any grouping indicators (parentheses or brackets) when copying it. Writing equations on one line, as we have to do here, requires some adjustments for clarity.

If the problem is

(4/9) * (x+3) = g

I can see no restrictions on the variables.

However, if this really is (as I suspect)

4 / [ 9 (x + 3) ] = g

then the (x+3) is a factor in the denominator of a fraction, and cannot be equal to zero.

In that case, the restriction is that x cannot be equal to -3.

And since there's no point sending people looking for restrictions that obviously aren't there, I'm guessing that's the correct statement of the problem.

Answer 4

x = (9g/4) - 3 and I don't think their are any restrictions. Restrictions are generally used when you have a variable in the denominator of a fraction or something similar. Like if x = (9/4g) - 3 then g could not equal 0 because then x would be undefined (you can't divide by 0) but I don't see any problems with your equation. x and g could be equal to any real number.

Edit: Okay I just read the post below me and he is correct. If your equation is in fact 4 / [9(x+3)] = g then yes the solution is the same but -3 is a restriction on the variable x for the same reasons I stated above (you can't divide by 0). I read it as if the problem were (4/9) * (x+3) = g which carries no restrictions.