I need help with two math problems ! ALGEBRA 1 !!!!!?

Question

if someone could help me solve these two problems that would be great and if you could include the steps that would be great too ! thanks ! here are the two problems

(p+q)squared+2(p+q)+1

(g-h)squared-2(g-h)+1

Answer 1

ewwwww trinomials or binomials or polynomials they suck

LOL

Answer 2

You can't solve these since they're not equations, but you can simplify them.

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Hint: Use ^ to indicate exponents

Examples:

^2 = squared

^3 = cubed

^4 = to the 4th power

^5 = to the 5th power

etc.

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(p + q)^2 + 2(p + q) + 1 =

Remember that a^2 + 2ab + b^2 = (a + b)^2

Given: (p + q)^2 + 2(p + q) + 1 = (p + q)^2 + 2(p + q)(1) + 1^2

Means: a = p + 1, b = 1

(p + q)^2 + 2(p + q) + 1 =

(p + q)^2 + 2(p + q)(1) + 1^2 =

(p + q + 1)^2

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(g - h)^2 - 2(g - h) + 1 =

Remember that a^2 - 2ab + b^2 = (a - b)^2

Given: (g - h)^2 - 2(g - h) + 1 = (g - h)^2 - 2(g - h)(1) + 1^2

Means: a = g - h, b = 1

(g - h)^2 - 2(g - h) + 1 =

(g - h)^2 - 2(g - h)(1) + 1^2 =

(g - h - 1)^2

Answer 3

the answer is 2

Answer 4

(p+q)² + 2(p+q) + 1

Let (p + q) = a

a² + 2a + 1

= (a + 1)²

= (p + q + 1)²

(g-h)²  - 2(g-h) + 1

let (g – h) = a

a² – 2a + 1

=(a – 1)²

= (g – h – 1)²

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