I need math help right now please!!!?

Question

give a parallel equation and a perpendicular equation given the point and line.

points- (3,-2) line 5x-4y=8

Answer 1

5x - 4y = 8

    - 4y = -5x+ 8

        y = 1.25x - 4  [to get the equation in slope-intercept form

                             [y= mx+b] divide everything by 4]

then you plug in your points [3, -2] and your slope [m or 1.25] to the slope intercept equation

-2 = 1.25(3) + b

-2 = 3.75     + b

-5.75 = b

then you plug that into your slope-intercept form to get your final answer: y= 1.25x + (-5.75)

Answer 2

(4/5)x - 2 = y (same equation given, but in slope-intercept form)

Change the '2' value to anything you please; it'll be parallel to the original (the slopes are the same).

For example: y = (4/5)x + 4

Perpendicular...

y = (-5/4)x - 2 (again, you can replace the '2' with whatever you please)

If your perpendicular equation has to go through the given point, then...

y = (-5/4)x + 1.75

Answer 3

Change to the form y = mx + b to find the slope, m

5x-4y=8

4y = 5x - 8

y = (5/4)x - 2

5/4 is the slope, and the parallel line will have the same slope.

The perpendicular line will have a slope of -4/5.

You now have m for the two lines.  To find b for each, substitute 3 and -2 for x and y in the equation y = mx + b, and solve for b for each equation.  Rewrite the equations of the lines as

y = (5/4)x + (whatever b is for the parallel line)

y = (-4/5)x + (whatever b is for the perpendicular line)