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I need some easy chemistry help, please?

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775gC9H12 x 1mol C9H12/120.21gC9H12

x 1molC9H11NO2/1mol C9H12 x 165.21g C9H11NO2/1mol C9H11NO2

(They're all substrates)

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  1. so you are calculating how many grams of  C9H11NO2 are associated with 775g of C9H12 , which are in an equation where they have a 1:1 mole ratio:

    775 g C9H12 @  165.21g C9H11NO2 / 120.21gC9H12 = 1065.11 grams

    your answer (3 sig figs) : 1070 grams of C9H11NO2

    (umless there were more sig figs in the "775"

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