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I need some help with my Algebra II homework?

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I need help finding a when:

2+{(sqrt)3a-2}= 9

I got 26.3, but that can't be right, can you show me hw to find what is?

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  1. sqrt(3a-2) = 7

    3a-2 = 49

    3a = 51

    a = 17


  2. 2+{(sqrt)3a-2}= 9

    add a minus 2 to the 9

    sqrt(3a-2) = 7

    square the 7

    3a-2 = 49

    add a 2 to the 49

    3a = 51

    divide the three and the 51

    a = 17
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