I need some math help?

Question

The width of a rectangle is fixed at 24 cm. What lengths will make the perimeter greater then 100 cm?

The length must be greater then ? cm

Answer 1

37 cm. cuz 24 + 24 is 48. the other two sides in order to equal 100 have to be 36 (100-48=72 and 72/2 is 36). but you said greater than 100 so 37 is ur answer.  

Answer 2

anything greater than 26. If the width is 24, and there are 2 width (one of each side) it makes 48. 100-48= 52, divided by 2 is 26. So if the length is 26 then adding up all the sides is 100. So anything more than 26, even 26.0000001 would give you +100 perimeter.

Answer 3

If the width is 24 cm and you need the perimeter to be over 100 cm then simply subtract 24 from 100 = 76. Divide this by 2 for the 2 sides and you are left with 38. So the length of each side must be 38 or over  

Answer 4

set them equal, forget about the inequality for now.

P = 100 = 2*24 + 2*L

L = 1/2(100 - 48) = 26

L > 26 cm

Answer 5

perimeter of rect= 2x + 2y

(2 x 24) + (2 x ?) > 100

2 x ? > 100-48

2 x ? > 52

  x > 26