I need to help on a math question?

Question

a baseball diamond is in the shape of a square, with the distance between consecutive bases of 90 feet. The second baseman wants to make an out at home plate. How far must he throw the ball?

help me please thnk you

Answer 1

If you draw this (or visualize it), from second base to home plate is the diagonal of the square. This cuts the square into two right triangles, each with a base and height of 90 (the sides of the square are 90 feet).

So, if we use the Pythagorean Theorem, we get:

90^2 + 90^2 = C^2

2*90^2 = C^2

2*8100 = C^2

16200=C^2

C=√16200 = 127.28 ft, to the nearest hundredth.

-IMP ;) :)  

Answer 2

Whoever wrote this question doesn't know baseball.  

The 2nd baseman doesn't stand on 2nd base.  You must

define where he is standing.  If he was on 2nd, then

he would be throwing the distance of the hypotenuse of

a right triangle defined by 2nd base, 3rd base, and home

plate.. Or the other triangle around 1st base.

Use Pythagoreon Theorem    C^2  = A^2  +  B^2

    where A &  B = 90 ft.

Answer 3

Let: x = distance from 2nd base to home plate.

x/2 = the distance from center pf the diamond to home plate.

Pythagorean Theorem:

c^2 = a^2 + b^2

c = 90

a = b = x/2

90^2 = 2(x/2)^2

4(8100/2) = x^2

x = 90*sqrt(2)

x = 127.28 ft

Answer 4

The diagonal from second to home creates to equal triangles, with the base and height equal to 90 feet and the hypotenuse= to the diagonal

The pythagoream theorem is what  you use to solve this

hypotenuse^2= side^2 + side^2

h^2= 90^2 + 90^2

h^2= 8100 + 8100=16200

h=sqrt 16200= 127.3 ft

Answer 5

x squared = 90 sq + 90 sq

x sq = 8100 + 8100 = 16200

x = 127.3 feet

Answer 6

Set up a right triangle with the three sides being Home-First, First-Second, and Second-Home.  The distance from home to first is 90 and from first to second is also 90.  Since those two sides of the triangle are equal, multiply 90*Square root of 2 or 1.414 to get 127.26 feet.

Answer 7

Pythagorean theorem

(90^2+90^2)^.5 = 127.3ft

Answer 8

In a square the following is always true:

The distance between 2 opposing corners (the diagonal) is

the distance between 2 connected corners ×sqrt(2)

so in this case the distance would be (exactly): 90×sqrt(2) feet

If you may use a calculator, then it's: 127.2792206 feet