I only need the factoring for these algebra problems, please look, please?

Question

ok so i have this whole test thing done except i dont have work shown for these three this is the one thing i have trouble with

all i need is the factoring

1. ( x - 3 / 2)^3 times (1 / x - 3) ^2 = x-3 / 8

2. x^2 - 9 / x + 2 times x^2 - 4 / x^2 - 9 = x^2 + x -12

3. x^2 + 5x + 4 / (x + 3)^2 divided by x + 1 / x ^2 - 9 = x^2 + x - 12 / x + 3

Answer 1

( x - 3)( x - 3)( x - 3) / 8 * (1 / x - 3( x - 3) = x-3 / 8

2 of the x-3 cancel, leaving (x-3)/8

x^2 - 9 / x + 2 (x^2 - 4 / x^2 - 9) = x^2 + x -12

((x+3)(x-3)/ x+2))*((x+2)(x-2)/(x+3)(x-3))  everything but x-2 cancels

x-2 does not = x^2+x-12

x+4(x+1)/ (x + 3)(x+3) divided by x + 1 /x -3(x+3).  Invert and multiply leaves x+4(x-3)/x+3  or  x^2 + x - 12 / x + 3