I really need your help with these math problems.?

Question

If it isn't too much, I will list 14 of the 150 problems from my homework i was assigned. I would like to see the work as well as the answer. Anything will help, even if you only know a few.

1) For what value of k is the graph of kx-7y+10=0 parallel to the graph of 8x-14y+3=0? For what value will the graphs be perpendicular?

2)Describe the transformations that have been done to f(x)=√x to get g(x), g(x)=4√(x-2)

3)How can you restrict the domain of y=(x^2)+2 to make it one-to-one?

4)Describe the transformations of f(x)=(-1/2)((x+3)^2)-5 as it compares to y=x^2

5)What is the long run behavior of f(x)= -3x^3+5x-6, and the same for g(x)=1/2x(x+5)^2(x-9)

6)State the roots and their multiplicity for g(x)=1/2x(x+5)^2(x-9)

7)Write (2+3i)/(4-2i) in standard(simplified) form

8)Simplify (x^3)(2x^4)(8x)

9) Simplify (36x^4y^3)/(12x^7y)

10)Describe the transformations of f as it compares to y=e^x, f(x)=3e^(x+5)

11)Convert to exponential form, log1000=4

12) Describe the transformations of f as it compares to y=logx, f(x)= 4+3logx

13)Change log(base 5)17 to a common log(base 10)

14) solve: 2^(6-x)=4^(2+x)

Answer 1

You need to do your own homework. You will never learn if you don't do it yourself.

Answer 2

1) kx-7y+10=0, 7y = kx + 10, y = k/7 x + 10/7

8x-14y+3=0, 14y = 8x + 3, y = 4/7 y + 3/14

to be parallel, k/7 must equal 4/7, so k = 4

to be perpendicular, k/7 must equal -7/4, so k/7 = -7/4, k = -49/4

Answer 3

Assuming this is a summer homework packet, it should all be stuff that you did last year. I did some of that in Algebra 1, and the rest in Algebra 2.

I'll give you some hints...

1) Put each of those into slope-intercept form by getting y alone on one side. Find k so that the slopes will be equal, and then so that the will be opposite reciprocals.

8) Multiply (x^3)(2x^4), then multiply the product by (8x).

9) Write (36x^4y^3) and (12x^7y) in factors. 36x^4y^3 will be 3 * 3 * 2 * 2 * x * x * x * x * y * y * y. You can do 12x^7y. Cross things out that appear in both the numerator and the denominator.

11) This is pretty straightforward, but requires knowing the properties of logarithms! The answer will be 1000 = x^y. Find x and y!

14) Write 4 as 2^2, so that you have 2^(6-x) = 2^(2)(2+x).

Good luck.

Answer 4

oh no --you do your own homework

Answer 5

owwwww...........