I would like to know how to calculate the area if the pipe is more than half full, i.e. may be 70% of its capa

Question

I would like to know how to calculate the area if the pipe is more than half full, i.e. may be 70% of its capa

Answer 1

You are looking for the Area of a segment.

http://mathforum.org/dr.math/faq/formula...

Answer 2

I think, what you would like to have is a means of computing the area occupied by the liquid in the pipe at a given liquid height because if it is the percent capacity that is given ,you just simply multiply the total internal area of the pipe with the given percent capacity then divide it by 100.

If this is what you need then:

Let:

r = inside radius of the pipe , which must be a given value

h = height of the water in the pipe, which must also be a given value

y = distance from the center of the pipe to the surface of the water

x =  half the width of the surface of the water in the pipe

2A = the angle of the sector of the unfilled portion of the pipe

(1). y = h - r

(2). A = arc cos(y/r)  in degrees

(3). x = r sin A

(4). Area = ((360 - 2A)/(360)) pi r^2 + xy

r, x, and y should be in the same units and the area is in square units

Answer 3

Need a lot more details, like dimensions.

How full a pipe is doesn't change the area! Perhaps you mean volume?