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If 21 Degrees Celsius has 100% heat energy, how much does -15 Degrees Celsius have in %heat energy?

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can you explain how it is?

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  1. "assuming" that enthapy = zero @ absolute zero

    21 C = 294 Kelvin  (with this being 100%)

    -15 C = 258 Kelvin

    % energy = 258 K / 298 K times 100 = 92.8%

    your answer is : 92.8% of the energy remains

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