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If 325 grams of butane are burned in air, how many grams of water are produced ??

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If 325 grams of butane are burned in air, how many grams of water are produced ??

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  1. 2C4H10 + 13O2 -> 8CO2 + 10H2O

    Moles of Butane = 325 / (4(12) + 10(1))

    Moles Butane :  Moles Water

    2 : 10

    1 : 5

    325 / (4(12) + 10(1)) : 5(325 / (4(12) + 10(1)))

    We have 5(325 / (4(12) + 10(1))) moles of water

    Mass = 5(325 / (4(12) + 10(1))) * (2(1) + 1(16))

    Mass = 504.31g

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