If 4a^2 + 5a + 4 = 5a^2 + 10, what are all possible values of a? ?

Question

it is multiple choice and i will give it to you

A. -1, 1/4

B. 3, 2

C. 3, 2, -1

D. No real solutions to this equation

E. -1

I worked this problem out and I get B, I will show my work

4a^2 + 5a + 4 = 5a^2 + 10

-4a^2 -4a^2

5a + 4 = a^2 + 10

-5a - 4 -4 -5a

0=a^2 - 5a + 6

I get choice B when I plug in 3 and 2

Answer 1

you are right

Answer 2

B is correct, but you don't need to guess and check.

0 = a^2 - 5a + 6

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factors into

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0 = ( a - 3 )( a - 2 )

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Now you have to figure out which values for a solve that equation. Zero times anything is zero, so if either set of parenthesis was equal to zero, then the equation is satisfied. Setting up an equation for both cases yields...

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0 = a - 3

a = 3

OR

0 = a - 2

a = 2

Answer 3

The correct answer is B

4a^2+5a+4=5a^2+10

move all of them to one side of the equation

5a^2-4a^2-5a+10-4=0

then we have

a^2-5a+6=0

and it is equal to (a-3)x(a-2)=0 so there are two possible values for a : 2&3

Answer 4

your answer is correct..

Answer 5

You know what you're doing

(a-3)(a-2)=0

then a-3=0

or a-2=0

So, a=2 or a=3

Answer 6

B

Answer 7

work:

4a^2+5a+4=5a^2+10

simplified: -1a^2+5a-6=0

-1(1)^2+5(1)-6=0

1+5-6=0

6-6=0

so your answer isn't B it's E.

Answer 8

0 = a² - 5a + 6

0 = (a - 3)(a - 2)

a = 2 , a = 3

OPTION B