If 5.0g of hydrogen is allowed to react with 5.0g of oxygen, what will be the mass of water produced?

Question

2. Butane reacts with oxygen to produce carbon dioxide and water. If 12.0g of butane were consumed, what mass of water should have been produced? (Show your work using unitary rates)

please help!

i actually asked this question already, but no one answered!

if you could answer one or both questions, thank you!

Answer 1

2 H2 + O2 >> 2 H2O

moles H2 = 5.0 / 2.016 = 2.48

Moles O2 = 5.0 / 32 =0.156 ( limiting reactant)

moles water = 2 x 0.156 = 0.312

Mass water = 0.312 x 18.02 =5.62 g

2 C4H10 +13 O2 >> 8 CO2 + 10 H2O

moles butane = 12.0 / 58.124 g/mol =0.206

moles water = 0.206 x 10/2 = 1.03

mass water = 1.03 x 18.02 =18.6 g