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If A:B=6:7andB:C=8:9, then find A:B:C.?

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If A:B=6:7andB:C=8:9, then find A:B:C.?

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  1. A:B:C = 1 :  (6/7)  :  (21/16)

    THATS IT!




  2. A/B= 6/7,  B=7A/6.

    B/C= 8/9, B= 8C/9.= 7A/6

       C/A= 63/48, A= 48C/63.= (48into8B/9)/63.

      A=  (384 B)/ 567.

  3. a/b = 6/7  @ b/c = 8/9 then a/c = 16/21 then A:B:C = 7:8:12

  4. A:B = 6:7   &   B:C=8:9

    As B is the common term in both a ratios

    Multiply ratio 1 by 8 and ratio 2 by 7 so that Ratios of B can be equated.

    48:56  & 56:63

    then it becomes  A:B:C = 48:56:63

  5. A/B = 6/7

    B/C = 8/9

    Multiplying both the equations,

    A/C = 16/21

    Putting A = 6, we get

    C = 63/8

    So, ratio is 6:7:63/8

    Multiplying by 8, we get

    A:B:C = 48:56:63

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  7. A:B=6:7 ==> 7A = 6B => A = (6/7)B

    B:C=8:9 ==> 8c = 9B => C =(9/8)B

    Hence A:B:C = (6/7) : 1: (9/8) = 48 : 56 : 63

    AJM

  8. A = 48

    B = 56

    C = 63

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  11. If A : B =6:7

      B:C=8 : 9 , WE SEE IN THESE RATIO B IS COMMON SO YOU WILL EQUAL THE VALUE OF "B"

           A : B =6:7 (MUNTIPLIED BY 8)

           B : C=8 : 9  (MUNTIPLIED BY 7)

    SO, WE GET

         A : B : C =48 : 56 :63

  12. A:B=6/7=48/56

    B:C=8/9=56/63

    A:B:C==48:56:63

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