If I was traveling at 70% the speed of light, one second in my spaceship would equal how many seconds on earth

Question

If I was traveling at 70% the speed of light, one second in my spaceship would equal how many seconds on earth

Answer 1

are you sure you have s spaceship?

Answer 2

At v=0.7, the Lorentz factor is 1/√(1-0.7^2) = 1.4.

An observer on Earth therefore observes that your clocks tick once every 1.4 seconds, rather than once per second, according to his watch, because he is at rest and you are travelling at 0.7c.

You in the spaceship therefore observe that clocks on Earth tick once every 1.4 seconds, rather than once per second, according to your watch, because you are at rest and Earth is travelling at 0.7c.

There is no absolute answer to the question "one second in my spaceship would equal how many seconds on earth?" because the answer depends on your frame of reference.

Answer 3

"4.9 seconds (70% of 7)"

that is wrong. it isnt a simple proportion.

you have to use the equation t=t0/sqrt(1-v^2/c^2)

so we get t=1/sqrt(.51)

t=1/.714142843

t= 1.40028008

so one second in your space ship is 1.40028008 seconds on earth from the point of view of someone on earth.

and the guy below me is roughly right on one half of his equation. .9c is 2.29415734 seconds on earth. but .95c is 3.20256308 seconds. for it to be 10 seconds you would have to be traveling .995c

EDIT: well, jose is missing part of his equation, but it comes out to be practically the same answer. but im forced to assume my equation is right considering jose doesnt think that mass and energy are interconvertable, so i wouldnt put too much stock in what he says.

EDIT2: yup just looked it up. he doesnt have the c^2 part of the equation, which is needed for the Lorentz factor