If a gram of water at sea level is heated from 5C to 23C, how much heat would be absorbed by the water?

Question

the text book did not explain that really well.... so, can someone explain that?

Answer 1

The answer in heat (not energy) is:

  

      (23-5) x 1 = 18 calories  

Answer 2

What you need to know is the temperature difference which is obviously 23-5 = 18 degrees K (or C)

Then you need to know the specific heat capacity of water which is 4.2J/g/K

so 18K*1g*4.2J/g/K=75.24J