If a star has a parallax of .050 seconds of arc, what is its distance in pc? in ly? in au?

Question

i tried to do these and it doesnt sound right to me. i think that

1 pc= 3.26 ly

1 pc=206265

how do i configure the .05 seconds of an arc into the equation?

Answer 1

.050 divide by 3.26 = 0.0153374 ly

Answer 2

A parallax of one second of an arc is equivalent to 206,265 times the distance from the earth to the sun, or 3.26 light-years.

A star with a parallax shift of one arcsecond would be one parsec away.

The Astronomical Unit is the average distance between the Sun and Earth. Its value is 149,597,870 km (about 93 million miles).

I will let you figure the answers out from here...

Answer 3

It's tricky, I know, but, rather than giving you the answer, let me show you how it's done with another set of figures:

A star that shows a paralax of 1 arcsecond is 3.26 ly distant.

A star that shows a paralax of 0.2 arcseconds is:

1 / 0.2 * 3.26 =   16.3 ly

in AU this is 16.3 * 206265 = 3.3*10^6 AU

Try plugging in your numbers...

Answer 4

Distance and parallax are inversely proportional. What are your answers that don't sound right?