If an observer is 200 feett....?

Question

from the building and the angle of elevation to the top of the building is 60 degrees, what is the height of the building?

PLEASE SHOW YOUR WORK=]

Answer 1

ill help you but nt give you the answer: draw a triangle with the 60 degrees at the top angle with a striahgt line down then a 90 degree angle at the bottom. the hypotenuse ( the largest side of the triangle) is 200 ft.

ok ill guess, its like you do somehting like     (200/ Sin 90)X( x/S60)

which then goes to like im really not sure from hti spoint onwards , but perhaps/maybe  (Sin 90 X x)/ (200 X Sin 60) then you can do the rest..

Answer 2

tan (theta) = opp/adj

theta = 60

opp = h

adj = 200 ft

200 * tan(60) = 346.41

Answer 3

Your configuration here is a right triangle where one leg is 200 feet (distance of the observer from the building) and the leg opposite the angle is the height of the building.

Let

h = height of the building

and so

tan 60 = h/200

and solving for "h",

h = 200(tan 60)

h = 200 (sqrt 3)

h = 346.4 feet

IN REALITY, the height of the building is a little bit more than 346.4 feet because this solutions assumes that the angle of elevation is measured from the ground.

This is not really so because the angle of elevation is reckoned from the horizontal line of sight of the observer's eyes (which should be approximately at least 5 feet from the the ground).

... just some technical details being thrown around here.