If friction is negligible, what is the resultant force on the sled?

Question

A 10-kg mass slides down a flat hill that makes an angle of 10 degrees with the horizontal. If friction is negligible, what is the resultant force on the sled?

Answer 1

Resultant force = weight of the mass along the plane of the hill

= mg sin 10 degree

= 10 * 9.8 * 0.17 N

= 16.7 N

Ans: 16.7 N

Answer 2

F= m*a

F= 10*9.8*sin  10

F= 17.01752141 N