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If sufficient acid is used to react completely with 72.9 g of magnesium, how much hydrogen will be produced?

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If sufficient acid is used to react completely with 72.9 g of magnesium, how much hydrogen will be produced?

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  1. Mg + 2HCl ---->  MgCl2 + H2

    1 mol Mg produces 1 mol H2

    The molar mass of Mg is 24.3 g/mol

    72.9 g Mg x ( 1 mol / 24.3 g) = 3.0 mol Mg

    3.0 mol Mg x (1 mol H2 / 1 mol Mg) = 3.0 mol H2

    3.0 mol H2 x (2.0. g / 1 mol ) = 6.0 g H2

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