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If the temperature of a gas does not change, but its volume doubles, what happens to the pressure?

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If the temperature of a gas does not change, but its volume doubles, what happens to the pressure?

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  1. Pressure is decreased to half.


  2. p1v1/t1=p2v2/t2 (combined gas law)

    v2=2*v1

    t1=t2

    therefore

    p1v1=p2v2 (boyle's law)

    p1v1=?p2*2v1

    p1v1=.5p2*2v1

    A: pressure halved. I thought the derivation would help.

  3. Reduces by half.

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