If triangle ABC~triangle DEF, AB=8, CB=4, and DE=12, find FE?

Question

If triangle ABC~triangle DEF, AB=8, CB=4, and DE=12, find FE?

Answer 1

AB/CB = DE/FE

8/4 = 12/FE

FE=6

Answer 2

if BC = 4 then FE= 4

Answer 3

fe==============4cm

Answer 4

since the two triangle are similiar

AB/DE = CB/FE

8/12 = 4/FE

8 FE = 48

FE = 6

Answer 5

FE = 6

Answer 6

TRI - ABC~ TRI DEF

    then,     AB = 8

                 DE = 12

                 CB = 4

    since,   TRI - ABC~ TRI DEF            

therefore,DE=AC (C.P.C.T)=12

                 AB =DF=8

                 CB = EF(FE)=4

                            hence proved!

*congruency means overlapping.