If two parents are heterozygous for rolling their tongue (dominate trait) and have a child, what's the %. ?

Question

What's the percent of the child NOT being able to roll his tongue (two heterozygous)?

If the two parents are homozygous dominate for this trait and then have a child, what is the change the child would NOT be able to roll his tongue?

Answer 1

25%.u'll get an idea if u draw punnet's checker board.wudn't waste my time drawing it cos this guy has already done it

Answer 2

25%, 0%.  Do a Punnet Square.

Let's say 'A' is dominant, and 'a' is recessive.

---A-----a-----

|

A.AA..Aa...

|

a.Aa...aa...

|

See? Only 25% of the offspring would statistically have homozygous recessive, which is the only way a recessive trait would show.

If both were homozygous dominant, there would be no recessive trait to pass on, and no chance of the child having the recessive trait.

Answer 3

There is a 25% chance that the child would NOT be able to roll his tongue. Consequently, if that child were to have his own child with the daughter of two heterozygous parents, the chance of their children would remain 25% for the next generation.

Answer 4

there would be a 75 pecent chance the child would roll his tongue and a 25pecent chance he would not