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If y varies directly with x and y= 6 and x= -3, find y when x= 4?

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If y varies directly with x and y= 6 and x= -3, find y when x= 4?

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  1. x = -3

    and y = 6.

    so, x/y = -3/6 = -1/2

    now, y = ? when x = 4.

    As x varies with y directly,

    x/y = -1/2

    or 4/y = -1/2

    or -y = 4 * 2 (by crossmultiplication)

    or y = -( 4*2 )

    or y = -8 (ANSWER)


  2. y=kx

    6=k(-3)

    6=-3k

    k=-2

    y=(-2)(4)

    y=-8

    im not sure.. but thats will be my answer!!

    ^_^

  3. L.H.S

    y=kx

    6=k(-3)

    6=-3k

    k=-2

    R.H.S

    y=(-2)(4)

    y="-8"

    ANSWER IS    " -8 "

  4. So if y varies directly with x , then the equation comes to,

    y= k*x.......where k is a constant,..........(1)

    when y=6 and x=-3 then

    solving equation  1 we get

    k= -2;

    now when x=4,then substituting the value of k in eq1

    we get,

    y= -2 * 4

    = -8 (ANSWER)

  5. "ans is  13" as on solving the eqn it is found that y=9+x

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