If you have a 25 mL sample of sulfuric acid and the unknown is neutralized by 43.28 mL of .1001 M NaOH how?

Question

get the molar concentration of sulfuric acid?

Answer 1

This is a acid base titration. Since a strong acid is reacting with a strong base we can assume that all of it reacts. To do this you use stoichiometry and mole ratios. A certain number of moles of acid reacts completely(so none is left over) with a certain amount of base. Since we know how much base reacts we can calculate how much acid is in the solution using a chemical equation and mole ratios. First write the chemical equation:

2NaOH(aq) + H2SO4(aq) --> Na2SO4(aq) + 2 H2O(l)

.04328L NaOH *(.1001moles/L) *(1mol H2SO4/2mol NaOH)= .002166moles of H2SO4

Molarity = moles/ Liters

Molarity = (.002166moles/ .025L) =

Molarity of H2SO4= .08665M