If you roll a pair of dice 72 times, how many of those rolls do you expect to have a diffrent of 0,1,6?

Question

Please explain how you know.

Answer 1

Assuming "diffrent" means difference,

If the difference is 6, it's time to stop playing. 0 expected.

Difference of 0 means the two are the same, probability is 6/36,

so 12 occurrences are expected.

Difference of 1 can occur as

(1-5)(2-6)  or (2-6)(1-5) = 10/36.  Thus 20 expected.

Other differences:

2:  (1-4)(3-6) x 2 = 8/36

3: (1-3)(4-6) x 2 = 6/36

4: (1-2)(5-6) x 2 = 4/36

5: (1)(6) x 2 = 2/36

6 + 10 + 8 + 6 + 4 + 2 = 36. That covers it.