If your mass is 73 kg, how much do you weigh?

Question

The gravity of a black hole is so strong that not even light can escape from within its surface or ″event horizon″. Even outside that surface, enormous energies are needed to escape. Suppose that you are 15 km away from the center of a black hole that has a mass of 1031 kg. If your mass is 73 kg, how much do you weigh?

Answer should be in Newtons.

Answer 1

are you asking just standard weight or relative to the black hole? you would normally multiply your mass in kg by gravitational field intensity of 9.8 m/s2 and the result of Kg-m/s2 is a newton

Answer 2

use the equation Force of gravity = universal gravitational constant x mass of you x mass of black hole / distance between you and the black hole.  then multiply the calulated force of gravity by your mass to get your weight.

Answer 3

I was under the impression, possibly incorrectly, that the reason a black hole had such enormous gravity, was due to its extremely high mass. You could then calculate the force of gravitational attraction using Newton's law of Universal gravitation. However, if your black hole has a mass of only 1031kg, the force of attraction cannot be very high

F = G*m1*m2/r²

F =  6.67*10^-11* 1031*73 /15000²

F = 6.67*10^-11 *1031 * 73 / 225,000,000

F = 2.19*10^-14N  Which is an extremely small force.

Did you possibly mean that the mass of the black hole was 10^31 kg?

If so:

F = 6.67*10^-11*73*10^13/225000000

F = 2.19*10^-4N  Which is also a very small force compared to the force that I believe a black hole exerts on matter nearby.

Or am I not understanding the question?

Answer 4

Weight(w) = Mass(m) x Gravitational Acceleration(g)

Therefore, w = 73 x 9.80665

               w = 715.88545 N

Answer 5

I am not sure, but I think you had better say your prays, Things don't look so promising for you, Go towards the light