Question:

In 1979 a river was 27ft below the bridge. Silt build-up in the bottom so the river was 19 1/2ft below in 1989

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Please give an equation for d, the distance of the river from the bridge, where t=0 represents 1979? If nothing is done about the silt, what year will the river reach the bridge?

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  1. This seems more like a math question. Not to mention that the river might be higher due to more rainfall in a particular year.

    Any, if we assume the silt build up is constant over time then the equation would be

    d= distance of river surface to bridge

    do = depth at time t =0

    da = depth at time t = 10 years

    t0 = t at time zero

    t10 = t at time equals ten years

    ∆d=da-do/(t10-t0)

    ∆d= 27-19.5/(10-0)

    ∆d= 0.75ft/year  

    If the river is rising at 0.75 feet per year then it will take

    27/0.75 = 36 years to reach the bridge

    So it will reach the bridge in 1979+36 = 2015

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