In 5 games, A won it once, B won three times and C won once. What is the probability that A, B & C win again?

Question

In 5 games, A won it once, B won three times and C won once. What is the probability that A, B & C win again based on another 5, 10 games etc ?

Thanks

Answer 1

This is not enough information to determine odds.

odds are not calculated from events that happened in the past, so whatever happend between games A B and C prior does not suggest ANY kind of pattern

To put it into perspective, A could have won all of those times even though B and C were both 10X as likely to win.

Odds are calculated form their portion of all possible outcomes wihtout knowing what those are and how  A B and C relate to them, you cannot calculate the odds of events A B and C happening.

If for some reason though this is a schoolwork question, and your teacher wants a number for an answer, the answer above is a misguided delusional way of calulating them that your teacher may eronously be teaching.  If you were to calculate them that way they woudl not actually be "odds" they would be percentages of sampled events that only make refference to events in thr past, not in the future.

If you wnat extra credit, have your teacher research a term known as the "gamblers fallacy" and how it relates to this question.

Answer 2

A has an 1/5 chance of winning in another 5 games,

B has a 3/5 chance of winning in another 5 games,

C has a 1/5 chance of winning in another 5 games,

to find the answer for a different number of games, simply divide that number of games by 5 and multiply that number by the numerator of the chances of winning when there are only 5 games played. For example if you want to find the probability of B winning for 10 games:

1.) Divide 10 by 5 - (2)

2.) Multiply the numerator of the probability of B winning in 5 games (3) by 2.

3.) Your answer is 6/10 simplified to 3/5

*This all based on experimental probability, if you need perfect probability, the answer to everything is 1/5