In C++ if you wanted to find an even or odd number you would...?

Question

go like

if(num%=0) ?!

how do u use % in that line? and i know that is wrong^^ how would u set it up though.

Answer 1

I think you would compare 'num % 2' to zero.  If true, the number is even.  % is the 'modulus' operator.

[edit]

When it says 'not an lvalue', it means that you can't *assign* 0 to 'num%2'.  Note that it would have been better if you hadn't left out the '2' in the example of what you tried.

'=' is ASSIGNMENT.  if you want to compare to 0, you have to use '=='.

Answer 2

if (a%2 == 0) {

  printf ("a is even.\n");

}

else {

  printf ("a is odd.\n");

}

Hope this helps.

Answer 3

the % is the mod operator, it is used like this:

num%2

it will return the remainder of num divided by 2.

so in your case:

if(num%2 == 0)

{

printf("%d is positibe", num);

}

Answer 4

if(num%=0) ?!

you are using assignment operator ( = ) ...

you are not assigning to to 0....

use bo0lean  which is ( == ) not an assignment operator which is ( = )

if(num % 2 == 0){

   printf("Even");

}

else{

   printf("Odd");

}

Answer 5

if you dont know this, you should be using C, not C++.

.........................................

sorry,

is it sumthin like...

int num;

{

if(num/2==false) ;       /* if the number divided by 2 doesnt work... */

then();

else();

}

Answer 6

Using % is incredibly inefficient and idiotic.  Whoever taught you that method is an idiot.  If I were to do this with C/C++ or Assembly Language, I would do it like this:

Look at the test number as a binary number.

If the test number is odd, then bit 0 (the right-most bit) would be 1.

Using the bitwise AND function, we can test if bit 0 is set.  Just do a bitwise AND with 1 and you can see this.



8 bit number examples:

00000010  test number (2 in decimal)

AND

00000001

=0 (the number is even)

00000101 test number (5 in decimal)

AND

00000001

= 1 (the number is odd)

C/C++ Example:

unsigned int testnum=5;

if (testnum & 1)

{

// code executes if number is odd

}

or you can do this:

if (!testnum & 1)

{

// code executes if number is even

}