In a 2nd story building, a ball is visible outside for 0.40s as it moves 5.15m from bottom of a windowto top?

Question

1. how long does it take before the ball reappears?

2. Calculate the maximum height of the ball above the top of the window

physics, 1d kinematics, easy, high school physics

Answer 1

You do not say at what angle the ball was launched. Was it straight up, perpendicular to the ground or was it launched at some particular angle such as 45 degrees?

You also do not state where the observer is with respect to the window. Is the bottom of the window above his eye-level?

The position of the ball at any time t is given by the parametric equations:

x = (VocosZ)t

y = (-1/2)(9.8)t^2 +(VocosZ)t , where

Vo = initial velocity

Z = angle of elevation at launch

t = time i seconds

9.8 = gravitational constant in m/s^2