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In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) a

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In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have normal fingers? (Hint: Use a Punnett square).

a. None

b. All

c. 1/4

d. 3/4

e. 1/2

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  1. Q: Does Nicole get your pay when you get a job from your education?

    A:No. She gets your job because she does the work to learn and qualify for it.


  2. e. 1/2

    the offspring are Bb or bb in proportion 1:1 so half of the offsprings will have normal fingers and the other half will suffer brachydactyl

  3. E. 1/2  

    Half of the children would have (bb) meaning that half would not have brachydacryly.

    Check this for a picture of the punnet square

    http://img37.picoodle.com/img/img37/4/7/...

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